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A miner finds a small mineral fragment with a volume of 11.5 cm3 and a mass of 57.4 g. what is the density of that mineral fragment?

User Carandraug
by
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2 Answers

5 votes
Density = mass/volume
= 57.4/11.5
= 4.99 g/cm^3
User Nicola Bizzoca
by
5.9k points
4 votes

Answer:


5 g/cm^3

Step-by-step explanation:

the density (amount of mass in a given volume) formula is


d=(m)/(v)

Data


m= 57.4 g\\v= 11.5 cm^3

Replace in the formula the data


d=(m)/(v)\\d=(57.4g)/(11.5 cm^3)\\d= 5 g/cm^3

User Tamura
by
6.0k points