Question

While travelling, john left destination a at 9 am. driving until 7 pm, he travelled a total of 500 miles. the next day, john left at 9 am and drove until 5 pm, covering 270 miles. what was the average speed for both days, while driving?

Answer 1

10 hours 500 miles

8 hours 270 miles

_________________

18 hours 770 miles

Average speed: 770 / 18 = 42.77;

Explanation:

Answer 2

Answer: 42.78 miles per hour.

Explanation:

Given: For first day,

Distance
`d_1=500` miles

Time
`t_1=10` hours

For next day

Distance
`d_2=270` miles

Time
`t_2=8` hours

For both days,

Total distance =
`d_1+d_2=500+270=770` miles

Total time taken =
`t_1+t_2= 10+8=18`hours

Now, the average speed for both days, while driving will be

`\text{Average speed}=\frac{\text{Total distance}}{\text{Total time}}\\\\=(770)/(18)=42.7777777778\approx42.78`

Hence, the average speed for both days, while driving = 42.78 miles per hour.