Question

Twice the sum of two numbers is 24. if one number is 2 times larger than the other, what is the smaller of the two numbers?

Answer 1

To find the smaller of the two numbers, we can assign variables and set up an equation. Solving the equation using appropriate steps, we find that the smaller number is 4.

Step-by-step explanation:

To solve this problem, let's assign variables to represent the two numbers. Let's call the smaller number 'x' and the larger number '2x' since it is stated that one number is 2 times larger than the other.

Twice the sum of two numbers is 24, so we can write the equation: 2(x + 2x) = 24. Simplifying this equation, we get 2(3x) = 24.

Dividing both sides of the equation by 2, we get 3x = 12. Finally, dividing both sides by 3, we find that x = 4. Therefore, the smaller of the two numbers is 4.

Answer 2

2(x+y)=24
2x=y

Use substitution. If y=2x, than we can substitute 2x for it in the other equation, because x and y equal the same things in both equations.

So using that we get 2(x+2x)=24

SIMPLIFY
2(3x)=24

DISTRIBUTE
6x=24.

DIVIDE: x=4.

If we substitute x into the original equations we get x=4 and y=8. Those are your two numbers.

Have a nice day! :)