Question

(2x+5)(3x−4) plz help

Answer 1

Answer:
6x^2 + 7x - 20

Process:
(2x+5)(3x-4)
= 2x(3x-4)+5(3x-4)
= (2x*3x)-(2x*4)+(5*3x)-(5*4)
= 6x^2 - 8x + 15x - 20
= 6x^2 + 7x - 20

Answer 2

`6x^(2)`+ 7x - 20

Explanation:

(2x+5)(3x−4)

=(2x+5)(3x+−4)

=(2x)(3x)+(2x)(−4)+(5)(3x)+(5)(−4)

=
`6x^(2)`−8x+15x−20

=
`6x^(2)`+7x−20