Question

there was a 6 square-foot piece of wrapping paper for a birthday present. It takes 3 3/8 square feet of the paper to wrap the present. How many pieces of 6 square-foot paper are needed to wrap 3 of these presents?

Answer 1

To wrap 3 presents, each requiring 3 3/8 square feet of paper, a total of two pieces of 6 square-foot wrapping paper are needed when rounded to the nearest whole piece.

Step-by-step explanation:

To determine how many pieces of 6 square-foot paper are needed to wrap 3 presents, where each present requires 3 3/8 square feet of paper, you first find the total square footage needed for the 3 presents. You multiply the amount of paper needed for one present (3 3/8 sq ft) by 3:

3 3/8 sq ft * 3 presents = 10 1/8 sq ft.

Then you determine how many 6 sq ft pieces are needed by dividing the total square footage needed by the amount of paper in one piece:

10 1/8 sq ft ÷ 6 sq ft/piece = 1.6875 pieces

Since you cannot have a fraction of a piece of wrapping paper, you would need to round up to the nearest whole number. Therefore, you would need two pieces of 6 square-foot wrapping paper to wrap 3 presents.

Answer 2

3 3/8 × 3 = x
distribute
3×3 + 3×3/8=x
9+9/8=x
9+1+1/8=x
10 1/8=x