Answer:
Option (3)
Explanation:
If the sides of a triangle are unequal then the measure of sides opposite to these angle will be in the order from least to greatest.
In ΔABC,
m∠CAB = 180°- (m∠B + m∠C)
= 180° - (25° + 27°)
= 180° - 52°
= 128°
Since, ∠CAB > ∠ABC ∠ACB
Therefore, a > b > c ---------(1)
Now from ΔADB,
m∠BAD + m∠ADB + m∠DBA = 180°
32° + m∠ADB + m∠35° = 180°
m∠ADB = 180° - 67°
= 113°
Since, m∠ADB > m∠DBA > m∠BAD
Therefore, c > d > e -------(2)
Combining both the inequalities,
a > b > c > d > e
Option (3) will be the answer.