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Find the exact value of sin (o)

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The best way to think about this value is to picture the graph of the "normal" sin wave. One period starts at (0, 0), goes up to a y value of 1 at an x value of
( \pi )/(2), goes back down to a y value of 0 at x =
\pi, goes down to a y value of -1 at x =
(3 \pi )/(2) and ends up completing one period at a y value of 0 and an x value of
2 \pi. We can see from that what the sin ratios are at each one of those x values. When x = 0, y = 0, so the sin of 0 is 0. Check your calculator to see that this is true, but understanding the graph tells you WHY it is true.
User Isa Souza
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