Question

Write the equation of the line that passes

through the point (-6, 1) and has a slope
of ½.

Answer 1

`(\stackrel{x_1}{-6}~,~\stackrel{y_1}{1})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{2} \\\\\\ \begin{array}c \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{ \cfrac{1}{2}}(x-\stackrel{x_1}{(-6)}) \implies y -1= \cfrac{1}{2} (x +6) \\\\\\ y-1=\cfrac{1}{2}x+3\implies {\Large \begin{array}{llll} y=\cfrac{1}{2}x+4 \end{array}}`