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A normal distribution of data has a mean of 90 and a standard deviation of 18. What’s the approximate z score for the value of 64
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A normal distribution of data has a mean of 90 and a standard deviation of 18. What’s the approximate z score for the value of 64

User Finferflu
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2 Answers

1 vote

Answer:

It is -1.4! just took test

Explanation:


User Datt Patel
by
6.2k points
0 votes


z = (x - u)/(sd)
when x is value (64)
u is mean (90)
and sd is satandard deviation (18)

so z = 64 - 90 / 18
z = -26 / 18 = -1.44
User Lukas Bystricky
by
5.6k points
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