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Is −x+0+(−x)=0 a true statement?

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Let's see it...

-x+0+(-x)=0 ???

There is a + before the parenthesis, the sign is the same.

-x+0-x = 0

Since the x have equal sign, we add them to get -2x

We have 2x - 0 = 0

Move the zero to the right, so 2x = 0

Divide both for 2...

x = 0

Substitute 0 to x, so -0+0+(-0) = 0

0 = 0 the statement is true
User Preet Shah
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