Question

What is the volume of 0.500 moles of nitrogen gas at 2.45 atmospheres pressure and a temperature of 303 K? (R=0.0821 L · atm/mol · K)

Answer 1

Hey there!

We use the Clapeyron equation :

P * V = n * R * T

2.45 * V = 0.500 * 0.0821 * 303

2.45 * V = 12.43815

V = 12.43815 / 2.45

V = 5.07 L

hope this helps !

Answer 2

5.08 L

Step-by-step explanation:

Given data

• Pressure (P): 2.45 atm

• Volume (V): ?

• Number of moles (n): 0.500 mol

• Ideal gas constant (R): 0.0821 L.atm/mol.K

• Temperature (T): 303 K

We can find the volume of gaseous nitrogen using the ideal gas equation.

P × V = n × R × T

V = n × R × T/ P

V = 0.500 mol × (0.0821 L.atm/mol.K) × 303 K/ 2.45 atm

V = 5.08 L