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Given that f(x) = 2x + 1 and g(x) = the quantity of 3x minus 1, divided by 2, solve for g(f(3)).
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Given that f(x) = 2x + 1 and g(x) = the quantity of 3x minus 1, divided by 2, solve for g(f(3)).

User Wasimsandhu
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f(x)=2x+1, g(x)=(3x-1)/2.
f(3)=7, g(7)=10. So g(f(3))=10.
User Dragonthoughts
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