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A telephone chord has 8 circular spirals, each spiral having a diameter of 12a+6b. find the total length of chord?

User Mushkie
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1 Answer

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The perimeter of one spiral: D*π, D=12a+6b⇒
(12a+6b)*π=6*π(2a+b)=18.85(2a+b)

A telephone chord has 8 circular spirals so total length of chord is:
8*18.85(2a+b)=146(2a+b)=292a+146b
The total length of telephone chord is 292a+146b.


User Sumit Bijvani
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