Question

If you have 3.50 moles of hydrogen and 5.00 moles of nitrogen to produce ammonia, which element is the reactant in excess? 3H2 + N2 → 2NH3

Answer 1

nitrogen

Step-by-step explanation:

The stoichiometry of the reaction says that
`H_(2)` and
`N_(2)` react 3:1 to form 2 moles of
`NH_(3)`, so, if you have 3,5 moles of H, which is equal to 1,75 moles of
`H_(2)`, and 5 moles of N, which are equal to 2,5 moles of
`n_(2)`. only
`(1,75 moles of H2)/(3)`=0.583 moles of
`N_(2)`, will react, leaving 1.917 moles of
`N_(2)` unreacted, and forming 0.583*2=1.166 moles of
`NH_(3)`