Question

Given: Circle O,

Chords
:
AB
||
CD,
Chords:
DE
≈
CE,
Arc
AB = 48°,
Arc
BC = 16°,find
Arc
CD.


HELP

Answer 1

In A Circle:
If AB || CD ⇒ BC = AD = 16°
AB + BC + CD + AD = 360°
AB + CD + 2BC = 360°
48° + CD + (2*16°) = 360°
CD = 360° - 48° - 32°
CD = 280°