Question

Acetone (fingernail-polish remover) has a density of 0.7857 g/cm3.what is the volume of what is the volume in milliliters of 7.64 g of acetone?

Answer 1

To find the volume of 7.64 g of acetone, we use the formula for density (Density = Mass / Volume), solve for volume, and plug in the mass and density values to obtain a volume of 9.72 mL.

Step-by-step explanation:

The question is asking us to find the volume in milliliters of 7.64 g of acetone, given that acetone has a density of 0.7857 g/cm3. To find the volume, we can use the formula:

Density = Mass / Volume

Rearranging this formula to solve for volume gives us:

Volume = Mass / Density

Now, plugging in the values we get:

Mass = 7.64 g

Density = 0.7857 g/cm3

Volume = 7.64 g / 0.7857 g/cm3

Performing the calculation yields:

Volume = 9.72 cm3

Since 1 mL is equivalent to 1 cm3, the volume of acetone is also 9.72 mL.

Answer 2

hey there!

1 cm³ = 1 mL

density = 0.7857 g/cm³

mass = 7.64 g

Volume = ?

density = mass / volume

0.7857 = 7.64 / V

V = 7.64 / 0.7857

V = 9.72 mL

hope this helps!