Question

Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)

Answer 1

`\sin d = (4)/(7)` ;
`\sin e = (√(33) )/(7)`

`\cos d = (√(33) )/(7)` ;
`\cos e = (4)/(7)`

`\tan d = (4)/(√(33) )` ;
`\tan e = (√(33) )/(4)`

Explanation:

For a right angled triangle with one of its angle α (alpha) :-

• 
  `\sin \alpha = (Side \: opposite \: to \: \alpha )/(Hypotenuse \: of \: the \: triangle)`

• 
  `\cos \alpha = (Side \: adjacent \: to \: \alpha )/(Hypotenuse \: of \: the \: triangle)`

• 
  `\tan \alpha = (Side \: opposite \: to \: \alpha )/(Side \: adjacent \: to \: \alpha )`

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According to the question ,

1) When α (alpha) = d

• 
  `\sin d = (4)/(7)`

• 
  `\cos d = (√(33) )/(7)`

• 
  `\tan d = (4)/(√(33) )`

2) When α (alpha) = e

• 
  `\sin e = (√(33) )/(7)`

• 
  `\cos e = (4)/(7)`

• 
  `\tan e = (√(33) )/(4)`