27,9,3... find the 7th term of the geometric sequence

asked Aug 23, 2019 94.5k views

1 vote

7.9k points

Please log in or register to add a comment.

0 votes

an= a1r^(n-1)
a7= 27(1/3)^(7-1)
= 27(1/3)^6
= (1/3)^(-3) * (1/3)^6
= (1/3)^(-3+6)
= (1/3)^3
= 1/27 #

Nagaraju V answered Aug 29, 2019

7.8k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers