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Graph ​ y+6=45(x+3) ​ using the point and slope given in the equation

User JasonG
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Explanation:

We have been given an equation y+6=45(x+3) in point slope form.

It says to use the point and slope from given equation to create the graph.

So compare equation y+6=45(x+3) with point slope formula

y-y1=m(x-x1)

we see that m=45, x1=-3 and y1=-6

Hence first point is at (-3,-6)

slope m=45 is positive so to find another point, previous point will move 45 units up then 1 unit right and reach at the location (-2,39).

Now we just graph both points (-3,-6) and (-2,39) and join them by a straight line. Final graph will look like the attached graph.

Graph ​ y+6=45(x+3) ​ using the point and slope given in the equation-example-1
User KiriSakow
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