Answer:
2. C. { 0, 1, 2}
3. B. 53
6. P = 14n + 10
Explanation:
2. The domain is the input values (or the x values)
The domain is { 0,1,2}
3. f(x) = 5x+3
where x is the number of minutes. We will let x = 10
f(10 ) = 5*10 +3
= 50+3
= 53
53 cars will pass
6. When we have 1 trapezoid, the perimeter is 5+5+8+6 = 24
When we have 2 trapezoids, the perimeter is 5+8+6+5+8+6 = 38
We add 14, when we add a second trapezoid
P = 14n + 10
p(1) = 14+10 Check for 1 trapezoid
p(2) = 14*2 +10 = 28+10 = 38 check for 2 trapezoids