Question

Find their perimeter and the area of trapezoid EFGH. Show all work needed to complete this problem. A=1/2(b1+b2)•h

Answer 1

Hello from MrBillDoesMath!

Answer:

Area = 28

Perimeter = 14 + 2 sqrt(17)

Discussion:

In our case

b1 = length of EH = 3 - (-3) = 3 + 3 = 6

b2 = length of FG = 4 - (-4) = 4 + 4 = 8

h = 2- (-2) = 2 + 2 = 4

So

Area = A = (1/2)h(b1+b2) = (1/2)(4)(6 + 8) = 2(14) = 28

Perimeter = length of EH + length FG + length of EF + length of HG

= 6 + 8 + ? + ?

From the Pythagorean theorem

HG = sqrt ( 1^2+ 4^2) = sqrt(17)

Similarly

EF = sqrt(17)

So Perimeter =

6 + 8 + sqrt(17) + sqrt(17)

= 14 + 2 sqrt(17)

Thank you,

MrB