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M<KGH=x+161,m<FGK=x+41,and m<FGH=180° Find x

User Charlesdg
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Answer: x = -11 ∠FGK = 30° ∠KGH = 150°

Explanation:

∠FGK + ∠KGH = ∠FGH Segment Addition Postulate

x + 41 + x + 161 = 180 Substitution

2x + 202 = 180 Simplify (added like terms)

2x = -22 Subtraction Property of Equality

x = -11 Division Property of Equality

∠FGK = x + 41 = (-11) + 41 = 30

∠KGH = x + 161 = (-11) + 161 = 150

User Michael Bird
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