Question

Jorge bought a crate of floor tiles for $95.94. The crate had 6 boxes of floor tiles. Each box contained 20 floor tiles . Write and slove an equation to dertermine the cost per box,b. Then write and slove a second equation to dertermine the cost per tile,t, to the nearest cent.

Answer 1

⇒
`6b=95.94` (equation to determine cost of one box)

cost of one box 'b' = $`15.99

⇒
`120t = 95.94` (equation to determine cost of per tile)

cost of one tile t = $0.7995.

Explanation:

Given :

Jorge bought a crate of floor tiles for $95.94.

The crate had 6 boxes of floor tiles.

Each box contained 20 floor tiles .

To Find :

Write and solve equation to determine the cost per box'b'.

Write and solve a second equation to determine the cost per tile't'

Solution :

Cost of one box = b

There are 6 boxes

So, cost of 6 boxes = $ 6b

Since Jorge bought 1 crate( = 6 boxes) of cost $95.94

⇒
`6b=95.94` (equation to determine cost of one box)

⇒
`b=(95.94)/(6)`

⇒
`b=15.99`

Thus cost of one box = $`15.99

Since 1 box 20 floor tiles

So, 6 boxes (=1 crate) contain tiles = 6*20 = 120 tiles

We are given that cost of 1 crate( = 6 boxes = 120 tiles) is $95.94

Cost of one tile = t

Cost of 120 tiles = $120t

⇒
`120t = 95.94` (equation to determine cost of per tile)

⇒
`t=(95.94)/(120)`

⇒
`t=0.7995`

Thus cost of one tile t = $0.7995.