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A local amusement park charges $21.50 per daily adult ticket and $14.75 per daily child's ticket. A group of 12 people paid $204.00 for tickets. Which system of equations could be used to find x, the number of adult tickets purchased, and y, the number of children's tickets purchased

2 Answers

3 votes

Answer:



x+y = 12



21.50x+14.75y=204.00


Explanation:

Given :

A local amusement park charges $21.50 per daily adult ticket and $14.75 per daily child's ticket.

Group of 12 people paid $204.00 for tickets.

To Find : System of equations could be used to find x, the number of adult tickets purchased, and y, the number of children's tickets purchased.

Solution :

Since group contains 12 people so no. of tickets are 12 .

Let out of 12 people no. of adults's tickets are x.

Let out of 12 people no. of children's ticket are y .



x+y = 12


Since charge of one adult ticket = $21.50

So, charge of x adult tickets = $21.50 x

Since charge of one child ticket = $14.75

So, charge of y children tickets =$14.75 y

And we are given that total amount paid by these 12 people = $204.00


Thus
21.50x+14.75y=204.00


Hence , System of equations could be used to find x, the number of adult tickets purchased, and y, the number of children's tickets purchased:



x+y = 12



21.50x+14.75y=204.00

User Lief Esbenshade
by
5.7k points
4 votes

Answer:


x+y=12


21.50x+14.75y=204

Explanation:

Let x be the number of adult tickets and y be the number of children's tickets.

We are given that there are total 12 people. Therefore, we can set:


x+y=12

Moreover, we are given that an adult ticket costs $21.50 and a child's ticket costs $14.75, therefore, cost of x adult tickets will be
21.50x and cost of y children's ticket will be
14.75y. We can form the second equation by setting the total cost of tickets as:


21.50x+14.75y=204

Therefore, the required system of equations that could be used to find x and y will be:


x+y=12


21.50x+14.75y=204

User Abou
by
6.3k points