Question

Solve for x

(x+7)^2-49=0

find the smaller and larger x
smaller x=
larger x=

Answer 1

`(x+7)^2-49=0\qquad\text{add 49 to both sides}\\\\(x+7)^2=49\iff x+7=\pm√(49)\\\\x+7=-7\ or\ x+7=7\qquad\text{subtract 7 from both sides}\\\\\boxed{x=-14\ or\ x=0}\\\\Answer:\\\\smaller\ x=-14\\larger\ x=0`

Answer 2

x = -14 and x=0

Explanation:

(x+7)^2-49=0

Add 49 to both sides

(x+7)^2-49+49=0+49

(x+7)^2 = 49

Take the square root of each side

sqrt((x+7)^2) = ±sqrt(49)

(x+7) = ±sqrt(49)

x+7 = ±7

Subtract 7 from each side to isolate x

x+7-7 = -7±7

x = -7±7

x = -7+7 and x = -7-7

x = 0 and x=-14