Answer:
–x^3 + 5x^2 – 8x + 1
Explanation:
You can observe that expanding f(2-x) will give you a sum that includes (2-x)³, so will have a -x³ term. This narrows the choices to one of the first two.
If x=0, then you have ...
... f(2) = 2^3 -2^2 -3 = 8 - 4 - 3 = 1 . . . . corresponds to the first selection
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Worked in detail
f(2-x) = (2-x)³ -(2-x)² -3 . . . . substitute 2-x for x in the expression for f(x)
... = (2³ -3·2²x +3·2x² -x³) -(2² -2·2x +x²) -3
... = -x³ +5x² -8x +1 . . . . . matches the first selection
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Using ...
... (a+b)³ = a³ + 3a²b +3ab² +b³
... (a+b)² = a² +2ab +b²