Answer:
df/dx = e^x(1/x+ ln(x))
Explanation:
f(x) = e^x * ln(x)
We can solve this by partial derivatives
df/dx = u dv + v du
let u = e^x and v = ln(x)
df/dx = e^x * 1/x + ln(x) * e^x
Factor out the e^x
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