Question

Pls help with this ..its to be submitted this monday.....pls pls pls

Answer 1

9pr = 2q^2

Explanation:

28.

px^2 + qx + r = 0

If one root is A then the other root is 2A

We have A + 2A = -q/p and A*2A = r/p

So 3A = -q/p so A = -q/3p and A^2 = r/2p so A = √ (r / 2p)

Equating these 2 equations:-

-q/3p = √(r / 2p)

q^2 / 9p^2 = r / 2p

9p^2r = 2pq^2

9pr = 2q^2 (answer)