6.4k views
4 votes
Given: ∆AKL, AK = 9 m∠K = 90° m∠A = 60° Find: P∆AKL The area of ∆AKL

User Vanguard
by
8.1k points

1 Answer

4 votes

Answer:


Explanation:


Given: ∆AKL, AK = 9 m∠K = 90° m∠A = 60° Find: P∆AKL The area of ∆AKL-example-1
User Neil Miller
by
8.3k points