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How would you graph 4x+2y=16

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Answer:


Explanation:

There are several ways in which you could do this.

One involves finding the x- and y-intercepts, plotting them and drawing a straight line through them. Starting with 4x + 2y = 16, let x = 0 to find the y-intercept: 2y = 16, or y = 8. The y-intercept is (0,8). Next, let y = 0 in 4x + 2y = 16 and solve for x; this leads to the x-intercept. 4x = 16, so x = 4. The x-intercept is then (4, 0). Plot (4,0) and (0, 8) and draw a straight line through these two points.

Another involves solving 4x+2y=16 for y, obtaining the equivalent in slope-intercept form of this equation. Subtracting 4x from both sides, we get 2y = 16 - 4x. Dividing all terms by 2 results in y = -2x + 8.

As before, the y-intercept is (0,8). Plot this point. Now use the slope, m = -2, to find another point on this line: Starting at (0,8), move 1 unit to the right (increasing x by 1) and then move 2 units down, arriving at (1, 6). Plot this point. Now draw a straight line through (1,6) and (0,8). Your result should look the same as the previous graph you drew.

User Ranjith KP
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