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Since we are given that ABC is congruent to JKL, then AB has to be equal to JK

therefore ---
14x+7=5x+34

Subtract 7 from both sides


14x=5x+27

Subtract 5x from each side


9x=27

Divide 9 on each side


x=3

Since, We are asked to find the length of AB and JK

plug in 3 for x


5(3)+34=15+34=49

User Sachin Kulkarni
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