Question

If f(x) = 1 – x, which value is equivalent to |f(i)|?
0
1
√2
√-1

Answer 1

`√(2)`

Explanation:

We plug in
`i` into
`f(x)` to get:

`f(i)=1-i`

Here,
`i` is the imaginary number
`i=√(-1)`

To get absolute value of an imaginary number, we use the following formula:

`a+bi=√(a^2+b^2)`

So absolute value of
`f(i)` is:

`|f(i)|=√((1)^2+(1)^2) \\=√(1+1) \\=√(2)`