Answer:
Mr. Wright taught 1,050 students in 25 years.
Explanation:
Given,
The number of students Mr. Wright taught = 18,
Also, every year the number of student is increased by 2,
So, in second year, the number of students = 18 + 2 = 20,
In third year = 20 + 2 = 22,
In fourth year = 22 + 2 = 24,
.............., so on,
Hence, we get an A.P. that shows the given situation,
18, 20, 22, 24, ............. till 25 years.....
First term, a = 18,
Common difference, d = 2,
And, number of terms, n = 25,
Hence, the total number of students that have been taught by him are,
![S_n=(n)/(2)[2a+(n-1)d]](https://img.qammunity.org/2019/formulas/mathematics/middle-school/zlxdeh4y1z86kc1buiv5zlr8j0r6ep4dw7.png)
![S_(25)=(25)/(2)[36+(25-1)2]](https://img.qammunity.org/2019/formulas/mathematics/middle-school/zu38ri84ce3fz6ki9b4hl10x1dh4noug7c.png)
![=(25)/(2)[36+24* 2]](https://img.qammunity.org/2019/formulas/mathematics/middle-school/3i1j9rnoobag0siq49nzxawj9yf0kfa7r5.png)
![=(25)/(2)[36+48]](https://img.qammunity.org/2019/formulas/mathematics/middle-school/kcsl5qsbv895nqa3z86366a4c9pbg6vbv8.png)



Third option is correct.