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A point P is placed exactly between two charges, Q1 and Q2. If the electric field experienced by point P due to charge Q1 is 1.5 × 105 newtons/coulomb and the field due to charge Q2 is 7.2 × 105 newtons/coulomb, what is the net electric field at point P?

A.
1.5 × 105 newtons/coulomb
B.
3.0 × 105 newtons/coulomb
C.
5.7 × 105 newtons/coulomb
D.
8.7 × 105 newtons/coulomb
E.
9.0 × 105 newtons/coulomb

2 Answers

3 votes

Answer:

D. 8.7 × 105 newtons/coulomb

Step-by-step explanation:

User TheRock
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Answer: D

Given data:

The electric field due to charge q₁ is (E₁) = 1.5 × 10⁵ N/C

The electric field due to charge q₂ is (E₂) = 7.2 × 10⁵ N/C

Determine the net electric field at point P (Enet) = ?

electric field measured in Newtons/coulomb

We know that,

The net electric field (Enet) is vector sum of E₁ and E₂ caused by the charge q₁ and q₂ respectively

Enet = E₁ + E₂

= (1.5 × 10⁵)+ (7.2 × 10⁵)

= 8.7 × 10⁵ Newtons/coulomb

The net electric field at point P is 8.7 × 10⁵ N/C

User Scottt
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