Question

Given: 1/3 x + y = 15. Which if the following are ordered pairs of this equation?

{(-3, 14), (0, 15), (3, 16)}
{(-3, 16), (0, 15), (3, 14)}
{(16, -3), (15, 0), (14, 3)}

Answer 1

The correct answer is the second answer----{(-3, 16), (0, 15), (3, 14)}

Answer 2

Option B - {(-3, 16), (0, 15), (3, 14)}

Explanation:

Given : Equation
`(1)/(3)x+y=15`.

To find : Which if the following are ordered pairs of this equation?

Solution :

Re-write the equation in linear equation format,

`y=-(1)/(3)x+15`

Taking point, (-3,16)

We substitute x=-3,

`y=-(1)/(3)(-3)+15`

`y=1+15`

`y=16`

It is true.

Taking point, (0,15)

We substitute x=0,

`y=-(1)/(3)(0)+15`

`y=0+15`

`y=15`

It is true.

Taking point, (3,14)

We substitute x=3,

`y=-(1)/(3)(3)+15`

`y=-1+15`

`y=14`

It is true.

Therefore, the ordered pairs are {(-3, 16), (0, 15), (3, 14)}.

So, option B is correct.