Question

Quinn returned home one summer's day to find it sweat-inducingly hot! He turned the air conditioner on and fell asleep. The room's temperature decreased by 0.5 ∘ Celsius each minute, and Quinn woke up 60 minutes later when it was 10 ∘ Celsius.

Answer 1

Cooling was bringing the temperature down 1 degree c every 2 minutes. 60min /2 =30°c . 10°c +30°c =40°c
The temperature was 40°c when he first returned home.

Answer 2

Answer: Temperature after 60 minutes is -20° C.

Explanation:

Since we have given that

Temperature at initial = 10° C

Decrement rate = 0.5°C per minute

Number of minutes taken = 60 minutes

According to question,

Temperature after 60 minutes would be

`10+60* -0.5\\\\=10^\circ C-30^\circ C\\\\=-20^\circ C`

Hence, Temperature after 60 minutes is -20° C.