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Find the value of < ACB

10


47


40


101

Find the value of < ACB 10 47 40 101-example-1
User Jtth
by
8.0k points

1 Answer

2 votes

Answer:

none of the above?

Explanation:

so the angles of the triangles are A1+A2+A3=360

so (4x+7)+(11x-9)+32=360

combine like terms

15x+30=360

isolate the variable

15x=330

x=22

angle ACB is 4x+7

4(22)+7=

88+7=

95

User Bastaspast
by
8.2k points

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