Question

Please help! Need answered! Please and thank you.

Answer 1

lim x→2 5 =5

The slope is 13

lim x→-2 x^2 -2 =2

Explanation:

lim x→2 5 =5

The limit of a constant is the constant

f(x) = x^2 +5x

We need to take the derivative

f'(x) = 2x+5

Then evaluate the derivative at x=4 (4,36)

f'(4) = 2*4 +5

= 8+5

= 13

The slope is 13

lim x→-2 x^2 -2 =2

Looking at the graph, the value of the function at -2 is about 2

We can also calculate it (-2)^2 -2 = 4-2 = 2

Answer 2

Answer: (a) 5

Explanation:

`\lim_(x \to 2) 5` means what is the y-value when x = 2 .

The given equation is: y = 5 so the y-value is 5 for all values of x

Answer: (c) 13

Explanation:

f(x) = x² + 5x

f'(x) = 2x + 5

f'(4) = 2(4) + 5

= 8 + 5

= 13

Answer: (c) 2

Explanation:

The question is asking what the y-value is when x = -2. The graph shows that the coordinate (-2, 2) is on the curve. So, when x = -2, y = 2.