Question

A 20 L cylinder of gas at 5.6 atm pressure at 35 degrees Celsius is heated to 95 degree Celsius and compared to 23 atm. What is the new volume?

Answer 1

5.8 L

Step-by-step explanation:

This looks like a case where we can use the Combined Gas Law to calculate the temperature.

p₁V₁/T₁ = p₂V₂/T₂ Multiply both sides by T₂

p₁V₁T₂/T₁ = p₂V₂ Divide each side by V₂

V₂ = V₁ × p₁/p₂ × T₂/T₁

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Data:

p₁ = 5.6 atm

V₁ = 20 L

T₁ = 35 °C = 308.15 K

p₂ = 23 atm

V₂ = ?

T₂ = 95 °C = 368.15 K

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Calculation:

V₂ = 20 × 5.6/23 × 368.15/308.15

V₂ = 20 × 0.243 × 1.19

V₂ = 5.8 L