Question

The molarity (M) of an aqueous solution containing 29.8 g of sucrose, C12H22O11, in 120 mL of solution is:

2.58 x 10–2 M.

7.26 x 10–4 M.

1.38 M.

0.726 M.

Answer 1

0.726 mol·L⁻¹

Explanation:

c = moles/litres

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Moles = 29.8 × 1/342.30

Moles = 0.087 06 mol

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Litres = 120 × 1/1000

Litres = 0.120 L

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c = 0.087 06/0.120

c = 0.725 mol·L⁻¹