Question

Please do this 24th prblm......

Answer 1

24.

The perimeter of a rectangle l × w is P = 2l + 2w.

We have l = 3x² - 2y² and w = x² + 3xy. Substitute:

P = 2(3x² - 2y²) + 2(x² + 3xy) use distributive property

P = (2)(3x²) + (2)(-2y²) + (2)(x²) + (2)(3xy)

P = 6x² - 4y² + 2x² + 6xy combine like terms

P = 8x² + 6xy - 4y²

Answer 2

6x^2 - 4y^2 + 2x^2 + 6xy

Explanation:

Each of the adjacent sides of the rectangle has a congruent, opposite sides. The perimeter is the sum of the lengths of the 4 sides.

P = 2(3x^2 - 2y^2) + 2(x^2 + 3xy)

P = 6x^2 - 4y^2 + 2x^2 + 6xy