Question

For the unbalanced equation, what is the coefficient for C5H10? ? C5H10 (l) +? O2 (g) →? CO2 (g) +? H2O (g) A. 2 B. 4 C. 10 D. 6 E. 1

Answer 1

1C5H10 + 15/2O2 => 5CO2 + 5H2O

Answer 2

Step-by-step explanation:

Balanced equation is defined as the equation which contains same number of atoms on both reactant and product side.

For example,
`C_(5)H_(10)(l) + O_(2) \rightarrow CO_(2)(g) + H_(2)O(g)`

Number of atoms on reactant side are as follows.

• C = 5

• H = 10

• O = 2

Number of atoms on product side are as follows.

• C = 1

• H = 2

• O = 3

So, to balance this equation we will multiply
`CO_(2)` on product side by 5 and also multiply
`H_(2)O` by 5. On the reactant side, we multiply
`O_(2)` by
`(15)/(2)`. Therefore, the balanced equation is as follows.

`C_(5)H_(10)(l) + (15)/(2)O_(2) \rightarrow 5CO_(2)(g) + 5H_(2)O(g)`

Thus, we can conclude that for the given unbalanced equation the coefficient for
`C_5H_10` is 1.