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What are the vertical and horizontal asymptotes for the function 3x^2/x^2-4

User Happyfirst
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Answer: vertical asymptotes: x = 2, x = -2

horizontal asyptote: y = 3

Explanation:


(3x^2)/(x^2-4)

Vertical Asymptotes are the restrictions on "x", which is denoted by the denominator being unequal to zero.

x² - 4 = 0

(x + 2)(x - 2) = 0

x + 2 = 0 and x - 2 = 0

x = -2 and x = -2

Horizontal Asymptotes are determined by the degree of the numerator (n) compared to the degree of the denominator (m) as follows:

  • If n > m , then no horizontal asymptote (use long division to find slant asymptote)
  • If n = m , then horizontal asymptote is coefficient of n divided by coefficient of m
  • If n < m , then horizontal asymptote is: y = 0

In the given problem, the degree of both the numerator and denominator is 2 so horizontal asymptote is:
y = (3)/(1) = 3

User Flyingbin
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