Question

The Ebbinghaus model of human memory may be used to model the amount of acquired knowledge a college student will retain after “cramming” for a final exam. The formula is p=(100-a)e^-b(0.07), where a and b vary from one person to another, and p is the percent of retained knowledge 1/2 day later when the student actually takes the final exam. If a = 20 and b = 1.2 for a typical student, how much of their “crammed” knowledge will that student retain at the moment of taking the final exam?

Answer 1

The correct answer is 93.6%

Explanation:

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Answer 2

Answer: 73.55%

Explanation:

p = (100-a) e^-b(0.07)

we have a = 20 and b =1.2

= (100-20) e^-(1.2)(0.07)

= 80(e^-0.084)

= 80(0.919431)

= 73.55%