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What are the zeros of the quadratic function f(x)=8x2-16x-15

User Nikem
by
6.3k points

2 Answers

1 vote

Answer: c on edge

Explanation:

x=1-square root 23/8 and x=1+square root 7

User Laurent K
by
6.6k points
5 votes

Answer:

x = 2.696, x = -0.696

Explanation:

We are given the following function of x and we are to find the zeros for the given quadratic function:


f(x)= 8x^2-16x-15

To find its zeros, we will use the quadratic formula:


x=(-b+-√(b^2-4ac) )/(2a)

Substituting the values in the formula where
a=8,
b=-16 and
c=-15.


x=(-(-16)+-√((-16)^2-4(8)(-15)) )/(2(8))


x=(16+-√(736) )/(16)


x=(16+27.13)/(16) ,
x=(16-27.13)/(16)


x = 2.696 ,
x=-0.696

Therefore, the solutions are 2.696 and -0.696.

User Andrei Stefan
by
6.1k points
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