Question

The center of a circle is at (-2, - 7) and its radius is 36 what is equation of the circle

A, (x-2)^2 +(y, - 7)^2 = 6

B, (x+2)^2 +(y, + 7)^2 = 6

C, (x-2)^2 +(y, - 7)^2 = 1296

D, (x+2)^2 +(y, + 7)^2 = 1296

Answer 1

ANSWER

The required equation is,


`{(x + 2)}^(2) + {(y + 7)}^(2) = 1296`

Step-by-step explanation

We want to find the equation of the circle given center
`(-2,-7)`

and radius
`36` units.


The equation of a circle given the radius,

`r`
and center

`(a,b)`

is given by the formula,


`{(x - a)}^(2) + {(y - b)}^(2) = {r}^(2)`

We substitute,


`a=-2,b=-7, r=36`

to obtain,


`{(x - - 2)}^(2) + {(y - - 7)}^(2) = {(36)}^(2)`

This will simplify to give us,


`{(x + 2)}^(2) + {(y + 7)}^(2) = 1296`

The correct answer is D.