Question

a bowling boal has a mass of 5 kg. what happens to its momentum when its speed increase from 1 m/s to 2 m/s?

Answer 1

Momentum also increases (doubles from 5 kgm/s to 10 kgm/s)

Step-by-step explanation:

the momentum is given by

`p=mv`

where
`p` is momentum,
`m` is mass of thebowling ball (
`m=5kg`), and
`v` is speed.

The momentum when
`v=1m/s` is:

`p=(5kg)(1m/s)\\p=5kgm/s`

and the momentum when
`v=2m/s` is:

`p=(5kg)(2m/s)\\p=10kgm/s`

so we can see that the momentum doubles from 5 kgm/s to 10 kgm/s.

Answer 2

change in momentum (p) = m. (v₂ -v1)

= 5. (2-1)

momentum = 5 m/s.