Question

Drag and drop numbers into the boxes so that the paired values are in a proportional relationship.

x 2 4 [A] 7 9
y 1 2 3 3.5 [B]

Options: 3 / 3.5 / 4.5 / 5 / 6

Answer Examlpe:

A= 6 and B= 3.5

Answer 1

the answer is 6

Step-by-step explanation: im 100% right this guy is wrong i repeat this guy is wrong!

Answer 2

A=6 and B=4.5

Explanation:

You are given table

`\begin{array}{cccccc}x&2&4&[A]&7&9\\y&1&2&3&3.5&[B]\end{array}`

If the paired values are in a proportional relationship, then

`(2)/(1)=(4)/(2)=([A])/(3)=(7)/(3.5)=(9)/([B]).`

Note that

`(2)/(1)=(4)/(2)=(7)/(3.5)=2,`

then

`([A])/(3)=2\Rightarrow [A]=6,\\ \\(9)/([B])=2\Rightarrow [B]=(9)/(2)=4.5.`