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The area of a playground is 204 yd^2 The width of the playground is 5 yd longer than its length. Find the length and width of the playground.

User GensaGames
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2 Answers

2 votes

Answer:

length = 17 yd, width = 12 yd

Explanation:

User Johnny Bones
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2 votes

Answer:

12

Explanation:

Assuming that the shape of the playground is rectangular, we know that the area of a rectangle is length x width.

Let the length = x

width = x + 5

x(x + 5) = 204

x² + 5x = 204

x² + 5x - 204 = 0

(x + 17)(x - 12) = 0

x = -17 and x = 12

However, since x represents the length of the playground, length cannot be negative. The only value possible is x = 12.

Therefore, the playground has a length of 12 yd and a width of 12 + 5 = 17 yd.

User Whistler
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