Question

Which of the following could be the equation of the function below?

Answer 1

it's strange, as according to ur question ,here is point(0,-3) but for the 3 graphs it provided, they do not touch(0,-3)
even I sub the point into the equation, i still cannot get the answer

Answer 2

`y=-2cos (2(x+\pi ))-1`

Explanation:

From the graph, we can see that y = -3 when x = 0.

So to check whether which of the given options is the equation of the given graph, we will set our calculator to the radian mode and then plug the value of x as 0.

1. y = -2 cos (4(x + pi)) - 1 = -2 cos (4(0 + pi)) - 1 = 3

2. y = 2 cos(x + pi) = 2 cos(0 + pi) = -1

3. y = -2 cos (2(x + pi)) - 1 = -2 cos (2(x + pi)) - 1 = -3

Therefore, the equation of this graph is y = -2 cos (2(x + pi)) - 1.